найти область определения функции у =√5-х² -4х /√х +4
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Ответил sedinalana
4
{5-x²-4x≥0
{x+4>0
x+4>0⇒x>-4
x²+4x-5≤0
x1+x2=-4 u x1*x2=-5
x1=-5 U x2=1
+ _ +
--------------[-5]-----(-4)-----------[1]--------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈(-4;1]
{x+4>0
x+4>0⇒x>-4
x²+4x-5≤0
x1+x2=-4 u x1*x2=-5
x1=-5 U x2=1
+ _ +
--------------[-5]-----(-4)-----------[1]--------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈(-4;1]
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