Question

Найти: g(8),g(-3),g(0) если g(x)=x²-10x

Answer 1

$g(x)=x^2-10x$
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$g(8)=8^2-10*8=64-80=-16$
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$g(-3)=(-3)^2-10*(-3)=9+30=39$
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$g(0)=0^2-10*0=0-0=0$