Question

Найдите значение, пожалуйста!
$( \sqrt{6} + \sqrt{2} ) {}^{2} - 2 \sqrt{3} (3 - \sqrt{2} ) =$
​

Answer 1

$(\sqrt6+\sqrt2)^2-2\sqrt3(3-\sqrt2)=6+2\sqrt{12}+2-6\sqrt3+2\sqrt6=\\\\=6+4\sqrt{3}+2-6\sqrt3+2\sqrt6=8-2\sqrt3+2\sqrt6$