Question

Найдите x из пропорции (1,6):

Answer 1

$1)\frac{x}{a+c}=\frac{c}{c^{2}-a^{2}}\\\\x=\frac{c(a+c)}{c^{2}-a^{2}}= \frac{c(a+c)}{(c-a)(c+a)}=\frac{c}{c-a}\\\\Otvet:\boxed{x=\frac{c}{c-a)}}\\\\\\6)\frac{2a-x}{3b-a}=\frac{6ab}{9b^{2}-a^{2}}\\\\2a-x=\frac{(3b-a)*6ab}{9b^{2}-a^{2}} =\frac{(3b-a)*6ab}{(3b-a)(3b+a)}=\frac{6ab}{3b+a}\\\\x=2a-\frac{6ab}{3b+a}=\frac{6ab+2a^{2}-6ab}{3b+a}=\frac{2a^{2}}{3b+a}\\\\Otvet:\boxed{x=\frac{2a^{2}}{3b+a}}$