Question

найдите точки экстремума функции f(x)=(x+1)^2(x+5)^2

Answer 1

2(x+1)(x+5)^2+(x+1)^2*2(x+5)=0
2(x+1)(x+5)(x+5+x+1)=0
x=-1; x=-5; x=-3
x(min)=-5; x(min)=-1; x(max)=-3