Question

Найдите производную функции ƒ(х) = (1/3*х3) - (1/2*х2)

Answer 1

$f'(x)=[frac{1}{3}*x^3-frac{1}{2}*x^2]'=[frac{1}{3}*x^3]'-[frac{1}{2}*x^2]'=\\ =frac{1}{3}*[x^3]'-frac{1}{2}*[x^2]'=frac{1}{3}*[3*x^{3-1}]-frac{1}{2}*[2*x^{2-1}]=\\ =frac{1}{3}*3*x^{2}-frac{1}{2}*2*x^{1} =x^2-x$