найдите область определения функции y=(5/(x+6))-(Sqrt[4-7x])
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Ответил yarovoe
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y=(5/(x+6))-√(4-7x)
{4-7х≥0 { -7x≥-4 { x≤4/7
x≠-6 , x≠-6, x≠0
------------------- -6--------------------------- 4/7----------------------->x
\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\
Ответ:(-∞;-6)∪(-6;4/7]
{4-7х≥0 { -7x≥-4 { x≤4/7
x≠-6 , x≠-6, x≠0
------------------- -6--------------------------- 4/7----------------------->x
\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\
Ответ:(-∞;-6)∪(-6;4/7]
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