найдите область определения функции 1)y=1/cosx 2)y=tgx/3
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Ответил sedinalana
0
1
cosx≠0⇒x≠π/2+πn,n∈z
x∈(-π/2+2πn;π/2+2πn,n∈z ) U (π/2+2πn;3π/2+2πn,n∈z)
2
-π/2+πn<x/3<π/2+πn
-3π/2+3πn<x<3π/2+3πn
x∈(-3π/2+3πn;3π/2+3πn,n∈z)
cosx≠0⇒x≠π/2+πn,n∈z
x∈(-π/2+2πn;π/2+2πn,n∈z ) U (π/2+2πn;3π/2+2πn,n∈z)
2
-π/2+πn<x/3<π/2+πn
-3π/2+3πn<x<3π/2+3πn
x∈(-3π/2+3πn;3π/2+3πn,n∈z)
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