Question

Найдите нули функции:
1) y=3x^2+x-2
2)f(x)=10-x^2

Answer 1

1) Y = 3X^2 + X - 2 
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Y = 0 ; X1 = 2/3 ; X2 = ( - 1 )
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3X^2 + X - 2 = 0 
D = 1 + 24 = 25 ; V D = 5
X1 = ( - 1 + 5 ) : 6 = 4/6 = 2/3 
X2 = ( - 6 ) : 6 = ( - 1 ) 
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X = 0 ; Y = ( - 2 )
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