Question

Найдите корень 4x-3/4x^2+10=1/5

Answer 1

$frac{4x-3}{4x^{2}+10}= frac{1}{5}\\4x^{2}+10=5(4x-3)\\4x^{2}+10=20x-15\\4x^{2}+10-20x+15=0\\4x^{2}-20x+25=0\\D=(-20)^{2}-4*4*25=400-400=0\\x=frac{20}{8}=2,5$