Question

Найдите интеграл.
$f(x) = sqrt{4x - 5}$
$f(x) = cos(4x - 2)$

Answer 1

$intlimits {sqrt{4x-5}} , dx = frac{1}4intlimits {(4x-5)^{frac{1}2}} , d(4x) =frac{1}4*frac{(4x-5)^{frac{1}2+1}}{frac{1}2+1}+C=\=frac{1}{4}*frac{2}{3}(4x-5)^frac{3}2+C=frac{1}6sqrt{(4x-5)^3}+C$

$intlimits {cos(4x-2)} , dx=frac{1}4intlimits {cos(4x-2)} , d(4x) =frac{1}4sin(4x-2)+C$