Question

(√n+3)(4-√n)-(√n-2)^2-8

Answer 1

(√n+3)(4-√n)-(√n-2)²-8=4√n-n+12-3√n-(n-4√n+4)-8=4√n-n+12-3√n-n+4√n-4-8=
=5√n-2n