Question

log5 (8х-12) - log5 4=log5 12

Answer 1

$log_5(8x-12)-log_54=log_512\ 8x-12 textgreater 0\ 8x textgreater 12\ x textgreater 1.5\ log_5( frac{8x-12}{4} )=log_512\ 2x-3=12\ 2x=15\ x=7.5$