Question

log4(3x+1)=log4(2x−1)

Answer 1

$log_{4}(3x + 1) = log_{4}(2x - 1) \ log_{4}(3x + 1) - log_{4}(2x - 1) = 0 \ log_{4}( frac{3x + 1}{2x - 1} ) = 0 \ frac{3x + 1}{2x - 1} = 4^{0} \ frac{3x + 1}{2x - 1} = 1 \ 3x + 1 = 2x - 1 \ x = - 2$