Question

log3²x-log3x-2>0
Помогите

Answer 1

$O.D.3.:;x>0\log_3x=t,;log_3^2x=t^2\t^2-t-2>0\t^2-t-2=0\D=1+4cdot2=9\t_{1,2}=frac{1pm3}2\t_1=-1,;t_2=2\log_3x=-1Rightarrow x=3^{-1}=frac13\log_3x=2Rightarrow x=3^2=9\\OTBET:;frac13;;9$