Question

log2x(x^2+x-2)=1
........................

Answer 1

ОДЗ
{x>0
{x≠1/2
{x²+x-2>0⇒x<-2 U x>1
x1+x2=-1 U x1*x2=-2⇒x1=-2 U x2=1
x>1
x∈(1;∞)
x²+x-2=2x
x²-x-2=0
x1+x2=1 U x1*x2=-2
x1=-1∉ОДЗ
х2=2

Answer 2

https://znanija.com/task/22565578 ПОМОГИТЕ ПРОШУ!!!!!!!!!!!