log1/6 (log5 49 * log7 125)
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Ответил uekmyfhfp
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log1/6_(log5_49 * log7_125) =
=log1/6_( 2*log5_7 * 3 log7_5) = log1/6_(6* log5_7 * 1/log5/7)=
=log1/6_(6*1) = log1/6_(6) = - log6_(6) = - 1
=log1/6_( 2*log5_7 * 3 log7_5) = log1/6_(6* log5_7 * 1/log5/7)=
=log1/6_(6*1) = log1/6_(6) = - log6_(6) = - 1
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