Question

log0.5(3x-1)+2=0 помогите решить пож

Answer 1

log(0.5)(3x - 1) + log(0.5)(1/4) = 0
log(0.5)(0.75x - 0.25) = 0
0.75x - 0.25 = 1
0.75x = 1 + 0.25 = 1.25
x = 1.25/0.75 = 5/3 - удовлетворяет ОДЗ
ОДЗ: 3x - 1 > 0, x>1/3

Ответ: x = 5/3

Answer 2

log0.5(3x-1)+2=0
log 1/2 (3x-1)=-2
(1/2)^(-2)=3x-1
4=3x-1
3x=5
x=5/3