Question

log (осн.2) 5 * log (осн.5) 7 * log (осн.7) 12 * log (осн.12) 25 * log (осн.25) 64

Answer 1

$log_ab=dfrac1{log_ba};;log_ab=dfrac{log_cb}{log_ca}$

 

$log_25log_57log_712log_{12}25log_{25}64=dfrac{log_57}{log_52}cdot\cdotlog_712log_{12}25log_{25}64=log_27log_712log_{12}25log_{25}64=\=dfrac{log_712}{log_72}log_{12}25log_{25}64=log_212log_{12}25log_{25}64=dots=\=log_264=6$