Log²3 x-4 log 3 x-12=0
Ответы на вопрос
Ответил mailforazi
0
Произведем замену 
![log_3^2x-4log_3x-12=0\ z^2-4z-12=0\ D=16+4*12=16+48=64=8^2\ z_{1,2}= frac{4{pm}8}{2} = left { {{z_1=-2} atop {z_2=6}} right. \ log_3x= -2\x=3^{-2}= frac{1}{9} \
\ log_3x=6\ x=3^6=729](https://tex.z-dn.net/?f=log_3%5E2x-4log_3x-12%3D0%5C+z%5E2-4z-12%3D0%5C+D%3D16%2B4%2A12%3D16%2B48%3D64%3D8%5E2%5C+z_%7B1%2C2%7D%3D+frac%7B4%7Bpm%7D8%7D%7B2%7D+%3D+left+%7B+%7B%7Bz_1%3D-2%7D+atop+%7Bz_2%3D6%7D%7D+right.+%5C+log_3x%3D+-2%5Cx%3D3%5E%7B-2%7D%3D+frac%7B1%7D%7B9%7D+%5C%0A%5C+log_3x%3D6%5C+x%3D3%5E6%3D729 "log_3^2x-4log_3x-12=0\ z^2-4z-12=0\ D=16+4*12=16+48=64=8^2\ z_{1,2}= frac{4{pm}8}{2} = left { {{z_1=-2} atop {z_2=6}} right. \ log_3x= -2\x=3^{-2}= frac{1}{9} \
\ log_3x=6\ x=3^6=729")
Новые вопросы