Question

lim при х->2 (х^2 -4)/(корень из 3х+3-3)

Answer 1

$lim _{xto :2}left(frac{x^2-4}{sqrt{3x+3-3}}right)=frac{2^2-4}{sqrt{3cdot :2+3-3}}=frac{2^2-4}{sqrt{6}}=frac{0}{sqrt{6}}=0$