Question

lim (4x^3-2x^2+5x)\(3x^2+7x)
x (стрелка) к 0

Answer 1

$\lim\limits _{x \to 0} \frac{4x^3-2x^2+5x}{3x^2+7x} = \lim\limits _{x \to 0} \frac{x(4x^2-2x+5)}{x(3x+7)} = \lim\limits _{x \to 0} \frac{4x^2-2x+5}{3x+7} = \frac{5}{7}$