Question

Как решить Методом Подстановки?

Answer 1

Ответ:

$\left\{\begin{array}{l}x+y=-2\\x^2-2xy+y^2=16\end{array}\right\ \ \left\{\begin{array}{l}y=-x-2\\x^2-2x\, (-x-2)+(-x-2)^2=16\end{array}\right\\\\\\\left\{\begin{array}{l}y=-x-2\\x^2+2x^2+4x+x^2+4x+4=16\end{array}\right\ \ \left\{\begin{array}{l}y=-x-2\\4x^2+8x-12=0\end{array}\right\ \left\{\begin{array}{l}y=-x-2\\x^2+2x-3=0\end{array}\right$

$\left\{\begin{array}{l}y=-x-2\\x_1=-3\ ,\ x_2=1\end{array}\right\ \ \left\{\begin{array}{l}y_1=1\ ,\ y_2=-3\\x_1=-3\ ,\ x_2=1\end{array}\right\ \ \ Otvet:\ \ (-3;1)\ ,\ (1;-3)\ .$