Question

как решить?
(3+2√2)*(1-√2)^2
(7+4√3)*(2-√3)^2

Answer 1

(3+2√2)*(1-√2)^2 =(3+2√2)(1-2√2+2)=(3+2√2)(3-2√2)=3²-(2√2)²=9-4*2=1

(7+4√3)*(2-√3)^2=(7+4√3)(4-4√3+3)=(7+4√3)(7-4√3)=7²-(4√3)²=49-16*3=1