Question

как решать?
${36x}^{2} - 60x + 25 = 0$
${(x + 3)}^{2} + 2(x - 6)(x + 3) + {(x - 6)}^{2} = 0$

Answer 1

${(6x - 5)}^{2} = 0 \ 6x - 5 = 0 \ x = frac{5}{6}$
${(x + 3 + x - 6)}^{2} = 0 \ (2x - 6) ^{2} = 0 \ 2x - 3= 0 \ x = frac{3}{2} =1.5$