Question

как это решить? *подробно*

Answer 1

$frac{5 c^{2}-c }{25 c^{2}-10c+1 }+ frac{4}{1-25 c^{2} }= frac{c(5c-1)}{(5c-1) ^{2} }+ frac{4}{(1-5c)(1+5c)}= frac{c}{5c-1}- frac{4}{(5c-1)(5c+1)} =$$=frac{5 c^{2}+c-4 }{(5c-1)(5c+1)}$

$1- frac{3}{5c-1}= frac{5c-1-3}{5c-1} = frac{5c-4}{5c-1}$

$frac{5 c^{2}+c-4 }{(5c-1)(5c+1)}: frac{5c-4}{5c-1} = frac{5(c+1)(c-0,8)*(5c-1)}{(5c-1)(5c+1)(5c-4)}= frac{(c+1)(5c-4)}{(5c+1)(5c-4)}= frac{c+1}{5c+1}$

$frac{11+1}{5*11+1}= frac{12}{56}= frac{3}{14}$