Question

Көбейткіштерге жіктеу (x+1)^3-3(x+1)^2+3(x+1)-1=?

Answer 1

(x+1)^3-3(x+1)^2+3(x+1)-1=((x+1)-1)³=(x+1-1)³=x³

Answer 2

$(\textup{x}+1)^3-3(\textup{x}+1)^2+3(\textup{x}+1)-1= \\ =\textup{x}^3+3\textup{x}^2+3\textup{x}+1-3(\textup{x}^2+2\textup{x}+1)+3\textup{x}+3-1= \\ =\textup{x}^3+3\textup{x}^2+3\textup{x}+1-3\textup{x}^2-6\textup{x}-3+3\textup{x}+2= \\ =\textup{x}^3+3\textup{x}^2-3\textup{x}^2+3\textup{x}-6\textup{x}+3\textup{x}+1-3+2=\textup{x}^3$