Question

Интеграл (3x^4-7x^6+15)

Answer 1

$int (3x^4-7x^6+15)dx=int3x^4dx-int7x^6dx+int 15dx=\=3 int x^4dx-7 int x^6dx+15int dx= frac{3x^5}{5} - frac{7x^7}{7} +15x+C=\frac{3}{5}x^5 - x^7 +15x+C$