Question

ХЕЛП ! ! !
$frac{5 x^{2} +12x-9}{20}$ = 0

Answer 1

$frac{5x^2+12x-9}{20}=0 \ \ 5x^2+12x-9=0 \ x_1=-3 \ x_2= frac{3}{5}$

Ответ: $-3; frac{3}{5}$

Answer 2

$frac{5 x^{2} +12x-9}{20} =0$
$left { {5 x^{2} +12x-9=0} atop {20 neq 0}} right.$

$5 x^{2} +12x-9=0$
$D=12^{2} -4*5*(-9)=144+180=324$
$x1= frac{-12- sqrt{324} }{5*2}= frac{-12-18}{10}= frac{-30}{10}=-3$
$x2= frac{-12+ sqrt{324} }{5*2}= frac{-12+18}{10}= frac{6}{10}=0,6$
Ответ:-3;0,6