Question

Help me pls pls pls pls pls pls pls pls pls pls pls pls pls pls pls pls ​

Answer 1

Ответ:

$\sqrt{6x + 5} = \sqrt{4 {x}^{2} + 7x - 5} \\ 6x + 5 = 4 {x}^{2} + 7x - 5 \\ 4 {x}^{2} + 7x - 6x - 5 - 5 = 0 \\ 4 {x}^{2} + x - 10 = 0 \\ d = 1 + 160 = 161 \\ x = \frac{ - 1 + \sqrt{161} }{8}$