(х-3) (Х - 2) = 6 (Х - 3)
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Ответил 25hjoerf10
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(х - 3)(х - 2) = 6(х - 3)
х² - 2х - 3х + 6 = 6х - 18
х² - 5х + 6 = 6х - 18
х² - 5х - 6х + 6 + 18 = 0
х² - 11х + 24 = 0
![D = (-11) ^{2} -4*24=121-96=25=5 ^{2} \ \ x_{1} = frac{11+5}{2} =8 \ \ x_{2} = frac{11-5}{2} =3 \](https://tex.z-dn.net/?f=D+%3D+%28-11%29+%5E%7B2%7D+-4%2A24%3D121-96%3D25%3D5+%5E%7B2%7D++%5C++%5C++x_%7B1%7D+%3D+frac%7B11%2B5%7D%7B2%7D+%3D8+%5C++%5C++x_%7B2%7D+%3D+frac%7B11-5%7D%7B2%7D+%3D3+%5C+ "D = (-11) ^{2} -4*24=121-96=25=5 ^{2} \ \ x_{1} = frac{11+5}{2} =8 \ \ x_{2} = frac{11-5}{2} =3 \")
Ответ: х₁ = 8; х₂ = 3.
х² - 2х - 3х + 6 = 6х - 18
х² - 5х + 6 = 6х - 18
х² - 5х - 6х + 6 + 18 = 0
х² - 11х + 24 = 0
Ответ: х₁ = 8; х₂ = 3.
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