Question

х-3:4х2+2•(6х+1:х-3+6х-1:х+3)

Answer 1

$frac{x-3}{4x^2}+2(frac{6x+1}{x-3}+frac{6x-1}{x+3})= frac{x-3}{4x^2}+2(frac{6x^2+18x+x+3+6x^2-18x-x+3}{x^2-9})= frac{x-3}{4x^2}+2(frac{12x^2+6}{x^2-9})=frac{x^3-9x-3x^2+27+96x^4+48x^2}{4x^2(x^2-9)}=frac{96x^4+x^3+45x^2-9x+27}{4x^2(x^2-9)}$