Question

(х^2-х+4)^2=(х^2-2х+4)^2

Answer 1

(xˇ2-x+4)ˇ2 = (xˇ2-2x+4)ˇ2
(xˇ2-x+4)ˇ2- (xˇ2-2x+4)ˇ2=0
(xˇ2-x+4+xˇ2-2x+4)(xˇ2-x+4-xˇ2+2x-4)=0
(2xˇ2-3x+8)(+x)=0
x1=0
2xˇ2-3x+8=0, D=9-64=-55,V(D)=V(-55)=i.V(55)
x2=1/4(3+i.V(55)=3/4 +i.V(55)/4
x3=3/4-iV(55/4