Question

геометрия тест
срочно!!

Answer 1

$\frac{ {2}^{ - 7} \times {2}^{ - 8} }{ {2}^{ - 9} } = \frac{ {2}^{ - 7 - 8} }{ {2}^{ - 9} } = \frac{ {2}^{ - 15} }{ {2}^{ - 9} } = {2}^{ - 15 - ( - 9)} = {2}^{ - 6} = \frac{1}{ {2}^{6} } = \frac{1}{64}$