Question

f ( x ) = 2x^3-3x^2+6 f' (-3); f' (3)

Answer 1

f(x)=$frac{x^2}{2}$-$frac{x}{3}$+6x

Answer 2

Спасибо :)

Answer 3

f'(x)=x-2x/3+6

Answer 4

f'(-3)= -3+2+6=5

Answer 5

f'(3)= 3-2+6=7