Question

допоможіть виконати!!!!!!!)!!!!!!

Answer 1

$\frac{a+4}{a^2-6a+9} : \frac{a^2-16}{2a-6} - \frac{2}{a-4} = \frac{a+4}{(a-3)^2} \cdot \frac{2(a-3)}{(a-4)(a+4)} - \frac{2}{a-4} = \\ =\frac{2}{(a-3)(a-4)} - \frac{2}{a-4} =\frac{2-2(a-3)}{(a-3)(a-4)} =\frac{2-2a+6}{(a-3)(a-4)} =\frac{-2a+8}{(a-3)(a-4)} =\\ =\frac{-2(a-4)}{(a-3)(a-4)} =- \frac{2}{a-3}$