Question

доказать торжество 

$2x^{2}(4x^{2}-3)(3+4x^{2})=32x^{6}-18x^{2}$

Answer 1

$2x^2(4x^2-3)(3+4x^2)=32x^6-18x^2\2x^2(4x^2-3)(3+4x^2)=2x^2(16x^4-9)\(4x^2-3)(3+4x^2)=16x^4-9\(4x^2-3)(3+4x^2)=(4x^2-3)(4x^2+3)$