Question

ДАЮ 30 БАЛЛОВ

Разложи на множители c3−g2c−gc2+g3.

(g− ?)^?⋅(g ? ?).

Answer 1

Пошаговое объяснение:

c³−cg²−c²g+g³ = с³–3с²g+3cg²–g³+2g³+2c²g–4cg²= (c–g)³+2g³+2c²g–4cg²=(c–g)³+2g(g²–2cg+c²)= –(g–c)³+2g(g–c)²= (g–c)²(–(g–c)+2g)= (g–c)²(c–g+2g) = (g–c)²(g+c)