ctg(-π/3-x/2)>=√3 решите
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Ответил nKrynka
5
πn ≤ (-π/3 - x/2) ≤ arcctg(√3) + πn, n∈z
π/3 + πn ≤ ( - x/2) ≤ π/3 + π/6 + πn, n∈z
π/3 + πn ≤ ( - x/2) ≤ π/2 + πn, n∈z
π/3 + πn ≤ ( - x/2) ≤ π/2 + πn, n∈z
- π ≤ x ≤ - 2π/3 + πn, n∈z
π/3 + πn ≤ ( - x/2) ≤ π/3 + π/6 + πn, n∈z
π/3 + πn ≤ ( - x/2) ≤ π/2 + πn, n∈z
π/3 + πn ≤ ( - x/2) ≤ π/2 + πn, n∈z
- π ≤ x ≤ - 2π/3 + πn, n∈z
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