Question

Cosп6-✓2sinп4+✓3tgп3

Answer 1

$Cosfrac{pi }{6}-sqrt{2}Sinfrac{pi }{4}+sqrt{3}tgfrac{pi }{3}=frac{sqrt{3} }{2}-sqrt{2}*frac{sqrt{2} }{2}+sqrt{3}*sqrt{3}=frac{sqrt{3} }{2}-1+3=frac{sqrt{3} }{2}+2$