Question

cos2x-sin^2(п/2-x)=-0 25

Answer 1

Решение
cos2x - sin∧2x = - 0,25
1 - 2sin∧2x - sin∧2x = - 1/4
-3sin∧2x = - 5/4
sin2x = - 5/12
2x = (-1)∧(n+1)arcsin(5/12) + πn, n∈Z
x= (1/2)* (-1)∧(n+1)arcsin(5/12) + πn, n∈Z