Question

Cократите дробь: a) 12ab/4a
B) 3c(1-c)/9c^2(c-1)​

Answer 1

$\frac{12ab}{4a} = 3b$

$\frac{3c(1 - c)}{9 {c}^{2} (c - 1)} = \frac{1 - c}{ - 3c(1 - c)} = - \frac{1}{3c}$

Answer 2

Ответ:

Объяснение:

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