Question

Цепочка превращения: CH3H8-C3H6-C3H7BR-C6H14-C3H6-C3H7OH

Answer 1

$C_3H_8-C_3H_6-C_3H_7Br-C_6H_{14}-C_3H_6-C_3H_7OH\ \ 1. C_3H_8 (Cr_2O_3, t)= C_3H_6 + H_2\ 2. C_3H_6 + HBr - C_3H_7Br\ 3. 2C_3H_7Br + 2Na (t) = 2NaCl + C_6H_{14}\ 4. C_6H_{14} (Pt, t) = C_3H_8 + C_3H_6\ 5. C_3H_6+HOH = C_3H_7OH$