Calculate ∆H0r for the reaction between copper (II) oxide and carbon, if carbon monoxide is formed in that reaction.
∆Н0f (CuO) = –162.0 kJ/mol, ∆Н0f (СО) = –110,6 kJ/mol
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Ответил HelloPrettySim
0
To calculate ∆H0r for the reaction between copper (II) oxide and carbon, we can use the following equation:
∆H0r = ∆H0f (products) - ∆H0f (reactants)
Plugging in the given values, we get:
∆H0r = (-110.6 kJ/mol) - (-162.0 kJ/mol)
= 51.4 kJ/mol
Therefore, ∆H0r for the reaction between copper (II) oxide and carbon is 51.4 kJ/mol.
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