Question

c++
b=1+|y-x|+(y-x)^2/2+|y-x|^3/3 ​

Answer 1

Ответ:loat z, x, y;

   cout << "x="; cin >> x;

   cout << "y="; cin >> y;

   z = (1 + sin(x + y)*sin(x + y)) * pow(y, 2) + cos(3.1415 - y)*cos(3.1415 - y);

   cout << "z=" << z << endl;

Объяснение: