Question

(b+4)^2
(c-3)^2
(9-q^2)
(25-4c^2)
(a^3-8)
(27-b^3)
(1000-c^3)

Answer 1

$(b+4)^{2}= b^{2}+8b+16$
$(c-3)^{2}= c^{2}-6c+9$
$(9-q^{2})=(3-q)(3+q)$
$(25-4c^{2})=(5-2c)(5+2c)$
$( a^{3}-8 )=(a-2)( a^{2}+2a+4 )$
$(27- b^{3})=(-b^{3}+27)=-(b-3)(b^{2}+3b+9)$
$(1000-c^{3})=(-c^{3}+1000) =-(c-10)(c^{2}+10c+100)$