Question

b 2x+78=10 4x+5b=12​

Answer 1

2x+78=10
2x=10-78
X= -34

4x+5b=12

Answer 2

Дано:

$bf 1) tt 2x+78=10 \ bf 2) tt 4x + 5b = 12$

Решение:

$bf 1) tt 2x + 78 = 10 \ tt 2x=10-78 \ tt 2x=-68 \ tt x=-68 div 2 \ bf x=-34$

$bf 2) tt 4x+5b=12 \ tt 4x=12-5b \ bf x=3-frac{5}{4}b$

$boxed{bf OTBET: x_1=-34; : : x_2=3-frac{5}{4}b}$