Question

& sin (2x-П/4)+1=0
7​

Answer 1

$sin left (2x - dfrac{pi}{4} right)+ 1 = 0$

$sin left (2x - dfrac{pi}{4} right) = -1$

$2x - dfrac{pi}{4} = -dfrac{pi}{2} + 2pi n, n in mathbb{Z}$

$2x= dfrac{pi}{4} - dfrac{pi}{2} + 2pi n, n in mathbb{Z}$

$2x = -dfrac{pi}{4} + 2pi n, n in mathbb{Z} | : 2$

$x = -dfrac{pi}{8} + pi n, n in mathbb{Z}$

Ответ: $x = -dfrac{pi}{8} + pi n, n in mathbb{Z}$