Question

алгебра
$\sqrt[3 ]{ \times } - 7 \sqrt[6]{ \times } + 12 = 0$
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Answer 1

пусть $\sqrt[6]{x}=t$,  t≥0, тогда:

t²-7t+12=0

D= 49-48= 1

t1= (7+1)/2= 4

t2= (7-1)/2= 3

$\sqrt[6]{x}=4$

x1= 4096

$\sqrt[6]{x}=3$

x2= 729