Question

Алгебра, 8 класс
Помогите решить пожалуйста ​

Answer 1

$\displaystyle\bf\\\frac{\sqrt{2} \cdot\sqrt{2}\cdot\sqrt{3} -\sqrt{3}\cdot\sqrt{3} \cdot\sqrt{2} -\sqrt{6} }{\sqrt{2} \cdot\sqrt{2}-\sqrt{6} -\sqrt{2} } =\\\\\\=\frac{\sqrt{2} \cdot\sqrt{2}\cdot\sqrt{3} -\sqrt{3}\cdot\sqrt{3} \cdot\sqrt{2} -\sqrt{2} \cdot\sqrt{3} }{\sqrt{2} \cdot\sqrt{2}-\sqrt{2} \cdot \sqrt{3} -\sqrt{2} } =\\\\\\=\frac{\sqrt{2} \cdot\sqrt{3}\cdot(\sqrt{2} -\sqrt{3} -1) }{\sqrt{2} \cdot(\sqrt{2}-\sqrt{3} -1) } =\frac{\sqrt{2}\cdot \sqrt{3} }{\sqrt{2} } =\sqrt{3}$